Generate random sequence of 4 numbers?

Can anybody explain me how to generate a random sequence of 4 numbers?

Like:

3,2,1,4
4,2,1,3
2,3,1,4

etc

Must be simple, but i'm either to stupid or to tired lol

math.randomseed(os.time())
 
local function generateFourRandomNumbers()
    local myString = ""
    for i = 1, 4 do
       myString = myString .. math.random(4) .. "," 
    end
    print(myString) -- okay you're left with a extra ,
end
 
for i = 1, 4 do
     generateFourRandomNumbers()
end

Wow, that was fast :)

Sorry i forgot to mention, any number cannot occur twice, and thats what happens with this code.

I got it:

local function generateFourRandomNumbers()
    local myString = ""
    repeat
                Choice = math.random(4)
                if string.find(myString, Choice) == nil then
                        myString = myString .. Choice 
                end     
    until string.len(myString) == 4
    print(myString) 
end
 
math.randomseed(os.time())
 
generateFourRandomNumbers()

then reject the number. check the new random number against a table. if the number is already in the table, reject, and generate a new number until it satisfies the eq.

Actually what you are tying to do is "Shuffle" the numbers.

You should search the forums for "shuffle", there have been several forum posts lately on how to shuffle a table.

local numbers = {1, 2, 3, 4}
 
local function shuffleTable(t)
    local rand = math.random 
    assert(t, "table.shuffle() expected a table, got nil")
    local iterations = #t
    local j
    
    for i = iterations, 2, -1 do
        j = rand(i)
        t[i], t[j] = t[j], t[i]
    end
end
 
shuffleTable(numbers)

I think Rob kind of nailed it much better, you do not need random numbers but you need shuffling of a fixed array.

you can read a bit more on shuffling here http://howto.oz-apps.com/2011/09/tables-part-2.html

cheers,

?:)

views:1858 update：2011/10/26 17:27:57


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